SOLUTION: Please help me solve the following equations: 50) a+4/2 = a+4/a 64) 4w-1/3w+6 - w-1/3 = w-1/w+2 Thank you.

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Please help me solve the following equations: 50) a+4/2 = a+4/a 64) 4w-1/3w+6 - w-1/3 = w-1/w+2 Thank you.      Log On


   

Question 87644: Please help me solve the following equations:
50) a+4/2 = a+4/a

64) 4w-1/3w+6 - w-1/3 = w-1/w+2
Thank you.
Answer by madhujiithcharu@yahoo.co.in(28) About Me  (Show Source):
You can put this solution on YOUR website!
a+4/2 = a+4/a => 1/2 = 1/a => a = 2
64)4w-1/3w+6 - w-1/3 = w-1/w+2
4w-1/3(w+2)- w-1/3 = w-1/w+2
4w-1-(w+2)(w-1)/3(w+2) = w-1/w+2
4w-1-w^2-w+2/3 = w-1
-w^2+3w+1 = 3w-3
-w^2 = -4
w^2 = 4
w = \/4 => w = 2, w=-2