SOLUTION: Enter the Equation of the directrix X^2+16y=0

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Question 876373: Enter the Equation of the directrix
X^2+16y=0

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 
Hi
x^2+16y=0
y = (-1/16)x^2 V(0,0), Opening downward: -1/16 < 0
1/(4p) = -1/16
p = -4
directrix is y = 4
the vertex form of a Parabola opening up(a>0) or down(a<0), y=a%28x-h%29%5E2+%2Bk
where(h,k) is the vertex and x = h is the Line of Symmetry
a = 1/4p, where the focus is (h,k + p)
With Directrix y = (k - p)