SOLUTION: Write an equation for a parabola with its focus at (-1, 0) and its directrix at x = 1. Write your answer in vertex form with fractions when needed.

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Write an equation for a parabola with its focus at (-1, 0) and its directrix at x = 1. Write your answer in vertex form with fractions when needed.      Log On


   

Question 876042: Write an equation for a parabola with its focus at (-1, 0) and its directrix at x = 1. Write your answer in vertex form with fractions when needed.
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi

Need to Know...............................................................

Standard Form of an Equation of a Circle is %28x-h%29%5E2+%2B+%28y-k%29%5E2+=+r%5E2 

Standard Form of an Equation of an Ellipse is %28x-h%29%5E2%2Fa%5E2+%2B+%28y-k%29%5E2%2Fb%5E2+=+1+ 

Standard Form of an Equation of an Hyperbola opening up and down is:%28y-k%29%5E2%2Fb%5E2+-+%28x-h%29%5E2%2Fa%5E2+=+1 

Standard Form of an Equation of an Hyperbola opening right and  left is:%28x-h%29%5E2%2Fa%5E2+-+%28y-k%29%5E2%2Fb%5E2+=+1 

the vertex form of a Parabola opening up(a>0) or down(a<0), y=a%28x-h%29%5E2+%2Bk

 the vertex form of a Parabola opening right(a>0) or left(a<0), x=a%28y-k%29%5E2+%2Bh

focus at (-1, 0) and its directrix at x = 1 Opening Left along y =0

the vertex form of a Parabola opening left(a<0), x=a%28y-k%29%5E2+%2B+h

x=a%28y%29%5E2+%2B+h  p = -1 (1 -1))/2  = 0 = h

x=a%28y%29%5E2+ a = 1/(4p) = 1/4(-1) = -1/4

x=%28-1%2F4%29+%28y%29%5E2+