SOLUTION: how do I solve 8 + log12(m-10) = 10
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Question 875610
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how do I solve 8 + log12(m-10) = 10
Answer by
rothauserc(4718)
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8 + log12(m-10) = 10
subtract 8 from both sides of =
log12(m-10) = 2
by definition of logarithm
m-10 = 12^2
m-10 = 144
m = 154