SOLUTION: A newspaper carrier has $3.80 in change. He has six more quarters than dimes, but four times as many nickels as quarters. How many coins of each type does he have?

Algebra ->  Customizable Word Problem Solvers  -> Numbers -> SOLUTION: A newspaper carrier has $3.80 in change. He has six more quarters than dimes, but four times as many nickels as quarters. How many coins of each type does he have?      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 875315: A newspaper carrier has $3.80 in change. He has six more quarters than dimes, but four times as many nickels as quarters. How many coins of each type does he have?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
(1) +q+=+d+%2B+6+
(2) +n+=+4q+
(3) +5n+%2B+10d+%2B+25q+=+380+
----------------------------
(1) +d+=+q+-+6+
Substitute (1) and (2) into (3)
(3) +5%2A%28+4q+%29+%2B+10%2A%28+q+-+6+%29+%2B+25q+=+380+
(3) +20q+%2B+10q+-+60+%2B+25q+=+380+
(3) +55q+=+440+
(3) +q+=+8+
and
(2) +n+=+4q+
(2) +n+=+4%2A8+
(2) +n+=+32+
and
(1) +d+=+q+-+6+
(1) +d+=+8+-+6+
(1) +d+=+2+
He has 32 nickels, 2 dimes, and 8 quarters
check:
(3) +5n+%2B+10d+%2B+25q+=+380+
(3) +5%2A32+%2B+10%2A2+%2B+25%2A8+=+380+
(3) +160+%2B+20+%2B+200+=+380+
(3) +380+=+380+
OK