SOLUTION: If a ball is tossed into the air from a height of 6 feet with a velocity of 32 feet per second, then its altitude at time t(in seconds) can be described by the function A(t)= -16t
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-> SOLUTION: If a ball is tossed into the air from a height of 6 feet with a velocity of 32 feet per second, then its altitude at time t(in seconds) can be described by the function A(t)= -16t
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Question 87496: If a ball is tossed into the air from a height of 6 feet with a velocity of 32 feet per second, then its altitude at time t(in seconds) can be described by the function A(t)= -16t^2 + 32t + 6
Find the altitude of the ball at 2 seconds. Answer by rapaljer(4671) (Show Source):
You can put this solution on YOUR website! A(t)= -16t^2 + 32t + 6 , when t=2:
A(2) = -16*2^2+32*2+6
A(2) =-16*4+ 64 + 6
A(2) =-64+64+6
A(2)=6 feet
