SOLUTION: "IF SIN=2/3 THEN REMAINING TRIGONOMETRIC FUNCTIONS"

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Question 874958: "IF SIN=2/3 THEN REMAINING TRIGONOMETRIC FUNCTIONS"
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
"IF SIN=2/3 THEN REMAINING TRIGONOMETRIC FUNCTIONS"
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cos%28x%29+=+sqrt%281+-+sin%5E2%28x%29%29+=+sqrt%281+-+4%2F9%29
= cos%28x%29+=+sqrt%285%29%2F3
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tan = sin/cos
cot = cos/sin
sec = 1/cos
csc = 1/sin
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If sin(x) = 2/3, x could be in Q1 or Q2.
That affects the signs of the other functions.