SOLUTION: I need help (conceptually) with finding the values of B and C when phase shift and period of trigonometric functions are known. Specifically:
y=cos(Bx-C) where the phase shift
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y=cos(Bx-C) where the phase shift
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Question 874849: I need help (conceptually) with finding the values of B and C when phase shift and period of trigonometric functions are known. Specifically:
y=cos(Bx-C) where the phase shift is pi/6 and the period is 3/5.
I thought I would be able to transform the equation into y=cos(B(x-C/B)) and then solve for B where 3/5=2pi/B -> B=10pi/3.
When I try to get my phase shift, however, I'm running into trouble.
I had PS=pi/6 -> pi/6=C/B -> C=pi/6 * 10pi/3 for 10pi^2/18. This is not convenient to work with (as most of the problems seem to be) so I feel like I'm not getting this process correct.
I appreciate you squaring me away. Answer by jsmallt9(3758) (Show Source):
You can put this solution on YOUR website! There is no "squaring away" to be done. With the period and phase shift you posted, your values for B and C are correct.
Perhaps you misread the problem or the problem has a typo. Perhaps the period and phase shift are not 3/5 or pi/6.
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