SOLUTION: A missile is shot from the ground with an initial velocity of 44 feet per second. The distance d above the ground after t seconds is given by: {{{ d= 44t-16t^2 }}} Please help

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Question 874829: A missile is shot from the ground with an initial velocity of 44 feet per second. The distance d above the ground after t seconds is given by:
+d=+44t-16t%5E2+
Please help me find the answer to this question using the equation I provided above:
How many seconds after the start is the missile at a height of 24 feet?
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
+24=+44t-16t%5E2+
4t^2 -11t + 6 = 0
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
x+=+%2811+%2B-+5%29%288%29+
x = 2 and x = 3/4
3/4 sec missile will reach a height of 24 feet