Question 874821: Solve: cos^2 theta - sin^2 theta = rad3/2 for theta in the domain [0deg, 360deg] Found 2 solutions by lwsshak3, jsmallt9:Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! Solve: cos^2 theta - sin^2 theta = rad3/2 for theta in the domain [0deg, 360deg]
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2x=30˚, 330˚
x=15˚, 165˚
You can put this solution on YOUR website! The solution provided by the other tutor is correct but incomplete. The end should be:
2x = 30 + 360n
2x = 330 + 360n
Dividing by 2:
x = 15 + 180n
x = 165 + 180n
Trying various integers for n, looking for x's between 0 and 360, we get:
x = 30 (when n = 0 in the first equation)
x = 210 (when n = 1 in the first equation)
x = 165 (when n = 0 in the second equation)
x = 345 (when n = 1 in the second equation)
Other n's result in x's that are either below 0 or above 360. So the solutions are 30, 165, 210 and 345.
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