SOLUTION: my algebra homework goes like this: use completing the square to find the standard form of each equation 16x^2 - y^2 - 4y - 68 = 0 and can you help me also on this one x^

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: my algebra homework goes like this: use completing the square to find the standard form of each equation 16x^2 - y^2 - 4y - 68 = 0 and can you help me also on this one x^      Log On


   

Question 874811: my algebra homework goes like this:
use completing the square to find the standard form of each equation
16x^2 - y^2 - 4y - 68 = 0
and can you help me also on this one
x^2 - 6y +y^2 + 5 = 0
and these ones too!!
x^2 - 4y - 12 = 0
y^2 + 12y + 4x + 12 = 0
x^2 + 4y^2 - 16 = 0
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Complete the square in x and y.
16x%5E2+-+y%5E2+-+4y+-+68+=+0
16%28x-0%29%5E2-%28y%5E2%2B4y%29-68=0
16%28x-0%29%5E2-%28y%5E2%2B4y%2B4%29-68%2B4=0
16%28x-0%29%5E2-%28y%2B2%29%5E2-64=0
16%28x-0%29%5E2-%28y%2B2%29%5E2=64
%2816%2F64%29%28x-0%29%5E2-%281%2F64%29%28y%2B2%29%5E2=1
%28x-0%29%5E2%2F2%5E2-%28y%2B2%29%5E2%2F8%5E2=1