SOLUTION: how would you find the center and the radius of 5(x-2)^2 + 5(y+6)^2 =2

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Question 874645: how would you find the center and the radius of
5(x-2)^2 + 5(y+6)^2 =2
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
how would you find the center and the radius of
5(x-2)^2 + 5(y+6)^2 =2
divide by 5
(x-2)^2+(y+6)^2=2/5
center: (2,-6)
radius=√(2/5)