SOLUTION: Dear Math. Tutor I am needing some assistance please. Stermine the number of real solutions of -x^2-6x-12=0 (I got 2, not sure if thats correct)?? Use the quadratic formula t

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Question 874521: Dear Math. Tutor I am needing some assistance please.
Stermine the number of real solutions of -x^2-6x-12=0 (I got 2, not sure if thats correct)??
Use the quadratic formula to find the exact values of the real solutions, if they exist. Give the solution set.
Use a calculator to find approximation for the answers. Round your answers to the nearest thousandth.
Found 2 solutions by josgarithmetic, Fombitz:
Answer by josgarithmetic(39630) About Me  (Show Source):
You can put this solution on YOUR website!
Simpler to multiply left and right members by -1 and have x%5E2%2B6x%2B12=0. The general solution contains an expression, 6%5E2-4%2A12, being value of -12%3C0. The equation has two complex solutions with imaginary parts.

You can use the general solution formula without (assuming) further guidance.

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
You can always check your answer in the original equation.
-2%5E2-6%28-2%29-12=0
-4%2B12-12=0
-4=0
False, so no it's not a solution.
-x%5E2-6x-12=0
x%5E2%2B6x%2B12=0
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
x+=+%28-6+%2B-+sqrt%28+6%5E2-4%2A1%2A12+%29%29%2F%282%2A1%29+
x+=+%28-6+%2B-+sqrt%28+36-48+%29%29%2F%282%29+
x+=+%28-6+%2B-+sqrt%28+-12+%29%29%2F%282%29+
x+=+%28-6+%2B-+sqrt%28+12+%29sqrt%28-1%29%29%2F%282%29+
x+=+%28-6+%2B-+2sqrt%28+3+%29i%29%2F%282%29+
x+=+-3+%2B-+sqrt%28+3+%29i+