Question 87411: 1. Jordan has a total of one hundred thirty nickels, dimes and quarters. He has three and a half times as many nickels as dimes, and one-half as many quarters as dimes. How much money does he have?
2. Austin has nickels, dimes and quarters. He has a total of $17.65. He has eleven fewer quarters than nickels and six times as many dimes as quarters. How many of each coin does he have?
Answer by josmiceli(19441)   (Show Source):
You can put this solution on YOUR website! n = number of nickels
d = number of dimes
q = number of quarters
To find how much money he has, find  ,  , and 
The answer is 1040 cents, or $10.40
--------------------------------
In this case,
n = number of nickels
d = number of dimes
q = number of quarters
as before, but what is known is how much money he has
and not the total number of coins
 (in cents)
Solve the 1st equation for n
Now find d and n in in terms of q
The answer is 19 quarters, 114 dimes, and 30 nickels
You can check answer by plugging values for d, n, and q into
the original equation
|
|
|
