SOLUTION: graph and find the center and radius of -2x-33+2y^2=-2x^2-6y

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Question 874074: graph and find the center and radius of -2x-33+2y^2=-2x^2-6y
Found 2 solutions by ewatrrr, Fombitz:
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi

2x^2-2x+2y^2 + 6y -33 = 0

 x^2-x+y^2 + 3y = 33/2 

(x-.5)^2 - 1/4 + (y+1.5)^2 - 9/4 = 33/2

(x-.5)^2 + (y+1.5)^2  = 33/2 + 5/2

(x-.5)^2 + (y+1.5)^2  = 38/2 

(x-.5)^2 + (y+1.5)^2  = 19

 c(.5, -1.5) r = √19

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
-2x-33%2B2y%5E2=-2x%5E2-6y
2x%5E2-2x%2B2y%5E2%2B6y=33
x%5E2-x%2By%5E2%2B3y=33%2F2
%28x%5E2-x%2B1%2F4%29%2B%28y%5E2%2B3y%2B9%2F4%29=33%2F2%2B1%2F4%2B9%2F4
%28x-1%2F2%29%5E2%2B%28y%2B3%2F2%29%5E2=66%2F4%2B1%2F4%2B9%2F4
%28x-1%2F2%29%5E2%2B%28y%2B3%2F2%29%5E2=19
Center : (1%2F2,-3%2F2)
R=sqrt%2819%29
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