SOLUTION: how do I solve: g(n)= n^2 + 4 + 2n h(n)= -3n + 2 Find (g x h)(1)

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Question 874018: how do I solve:
g(n)= n^2 + 4 + 2n
h(n)= -3n + 2
Find (g x h)(1)
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi

(g x h)(n) = -3n(n^2+2n+4) + 2(n^2+2n+4) 

(g x h)(n) = -3n^3-4n^2 -8n + 8

(g x h)(1) = -3n^3-4n^2 -8n + 8 = -3 -4 -8 + 8 = -7