SOLUTION: Six apples and 1 pear cost $2.00. At the same store, 3 apples and 6 pears cost $2.10 Find the cost of one apple and the cost of one pear. Equation & answer please. Thank You s

Algebra ->  Average -> SOLUTION: Six apples and 1 pear cost $2.00. At the same store, 3 apples and 6 pears cost $2.10 Find the cost of one apple and the cost of one pear. Equation & answer please. Thank You s      Log On


   

Question 873917: Six apples and 1 pear cost $2.00. At the same store, 3 apples and 6 pears cost $2.10 Find the cost of one apple and the cost of one pear.
Equation & answer please.
Thank You so much
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
If "Six apples and 1 pear cost $2.00", then 6a%2B1p+=+2 where 'a' is the cost for a single apple and p is the cost for a single pear.

If "3 apples and 6 pears cost $2.10", then 3a%2B6p+=+2.10

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The two equations you'll use are

6a%2B1p+=+2
3a%2B6p+=+2.10


Solve for p in 6a%2B1p+=+2 to get p+=+2-6a

Then plug this into the second equation to get

3a%2B6p+=+2.10

3a%2B6%282-6a%29+=+2.10


Solving that equation for 'a' will give you the cost for a single apple. Once you know the value of 'a', plug it into p+=+2-6a to find the value of p (the cost for a single pear)