Question 873754: An integer is 3 more than another. If the product of the two integers is 130, then find the integers.
Can you please show with steps? Answer by ewatrrr(24785) (Show Source):
You can put this solution on YOUR website! n(n+3) = 130 Set UP
n^2 + 3n - 130 = 0 Solve for x
(n+13)(n-10) = 0
n = -13, 10
So two pairs of Integers
-13 & -10 0r 10 & 13