Question 873743: Let x be a random variable representing dividend yield of Australian bank stocks. We may assume that x has a normal distribution with = 2.8%. A random sample of 16 Australian bank stocks has a sample mean dividend yield of 8.91%. For the entire Australian stock market, the mean dividend yield is = 6.4%. If you wanted to test, at a .05 level of significance, to determine if these data indicate that the dividend yield of all Australian bank stocks is higher than 6.4% what is the critical value that you would use?
Answer by ewatrrr(24785)   (Show Source):
You can put this solution on YOUR website!
Hi
DF = 15, critical value = 2.13 for .05 level of significance
DF Probability, p
0.1 0.05 0.01 0.001
1 6.31 12.71 63.66 636.62 1
2 2.92 4.3 9.93 31.6 2
3 2.35 3.18 5.84 12.92 3
4 2.13 2.78 4.6 8.61 4
5 2.02 2.57 4.03 6.87 5
6 1.94 2.45 3.71 5.96 6
7 1.89 2.37 3.5 5.41 7
8 1.86 2.31 3.36 5.04 8
9 1.83 2.26 3.25 4.78 9
10 1.81 2.23 3.17 4.59 10
11 1.8 2.2 3.11 4.44 11
12 1.78 2.18 3.06 4.32 12
13 1.77 2.16 3.01 4.22 13
14 1.76 2.14 2.98 4.14 14
15 1.75 2.13 2.95 4.07 15
16 1.75 2.12 2.92 4.02 16
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