SOLUTION: I am supposed to Evaluate if possible the following: sqrt of 36, I get sqrt of 36...then there is the sqrt of 9/16, and I get sqrt of 9/16, and I have not been able to figure out

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: I am supposed to Evaluate if possible the following: sqrt of 36, I get sqrt of 36...then there is the sqrt of 9/16, and I get sqrt of 9/16, and I have not been able to figure out       Log On


   

Question 87359: I am supposed to Evaluate if possible the following:
sqrt of 36, I get sqrt of 36...then there is the sqrt of 9/16, and I get sqrt of 9/16, and I have not been able to figure out how to evaluate ^3sqrt1/64...Can someone PLEASE HELP ;0/ Thanks
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
sqrt%2836%29=6 This is true since 6%2A6=6%5E2=36
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sqrt%289%2F16%29

sqrt%289%29%2Fsqrt%2816%29 Break up the square root using the identity sqrt%28x%2Fy%29=sqrt%28x%29%2Fsqrt%28y%29

3%2F4 Evaluate the individual square roots

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root%283%2C1%2F64%29

root%283%2C1%29%2Froot%283%2C64%29 Break up the cube root using the identity root%28n%2Cx%2Fy%29=root%28n%2Cx%29%2Froot%28n%2Cy%29


1%2F4 Take the cube root of 1 to get 1. Take the cube root of 64 to get 4