Question 873522: a right triangle has a hypotenuse of 15 and one leg of length of 5. determine the length of the other leg Answer by harpazo(655) (Show Source):
x^2 + 5^2 = 15^2
x^2 + 25 = 225
x^2 = 225-25
x^2 = 200
Take square root of both sides.
Let sqrt = square root for short
sqrt(x^2) = sqrt(200)
x = sqrt(100) times sqrt(2)
x = 10*sqrt(2)
The missing leg has a length of 10*sqrt(2)
