SOLUTION: I need someone to show me how to convert this equation to standard form. y^2-4y+12x-8=0

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Question 873402: I need someone to show me how to convert this equation to standard form.
y^2-4y+12x-8=0
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
The standard form is %28y+-k%29%5E2+=+4p%28x+-h%29
(y-2)^2 - 4 +12x - 8 = 0
(y-2)^2 = -12x + 12
(y-2)^2 = -12(x - 1)