SOLUTION: For all values of x in the interval 0 is less than or equal to x which is less than or equal to 360 that satisfy the equation 4cos^2x-5sinx-5=0. Express your answer to the nearest
Algebra ->
Functions
-> SOLUTION: For all values of x in the interval 0 is less than or equal to x which is less than or equal to 360 that satisfy the equation 4cos^2x-5sinx-5=0. Express your answer to the nearest
Log On
Question 873174: For all values of x in the interval 0 is less than or equal to x which is less than or equal to 360 that satisfy the equation 4cos^2x-5sinx-5=0. Express your answer to the nearest tenth of a degree. Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! For all values of x in the interval 0 is less than or equal to x which is less than or equal to 360 that satisfy the equation 4cos^2x-5sinx-5=0. Express your answer to the nearest tenth of a degree.
***
For interval: 0 ≤ x ≤ 360˚
4cos^2x-5sinx-5=0
4(1-sin^2x)-5sinx-5=0
4-4sin^2x-5sinx-5=0
-4sin^2x-5sinx-1=0
4sin^2x+5sinx+1=0
(4sinx+1)(sinx+1)=0
..
4sinx+1=0
sinx=-1/4
x=194.5˚,345.5˚
..
sinx+1=0
sinx=-1
x=180˚
(