Question 87307: 1. Factor completely. 64x^3-48x^2-4x+3
I have came up with 8x^2(8x-6)-4x+3 I don't know what to do with the 4x+3.
2. Factor completely. 49x^3y-112x^2y^2+64xy^3
On this question i have tried using -2,-32; -4,-16; -8,8 to factor but they aren't working.
Answer by rossiv53(27)   (Show Source):
You can put this solution on YOUR website! 1. Fctor by grouping the first two terms and the last two terms.
So, (64x^3-48x^2)-(4x-3)
Factor out common factors..
This gives you 16x^2(4x-3)-(4x-3)
Factored form is (16x^2-1)(4x-3)
2. Only common factors in second equation are xy.
This gives you xy(49x^2-112x^2y+64y^2)
You can factor this further by grouping in the second term.
xy(49x^2-56xy-56xy+64y^2)
7x(7x-8y)-8y(7x-8y)
So, answer is xy(7x-8y)(7x-8y)or xy(7x-8y)^2
Good luck.
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