SOLUTION: An investment club wants to invest $60,000 in two simple interest accounts. One account earns 9.4% annual simple interest and the other account earns 10.9% annual simple interest.

Algebra ->  Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: An investment club wants to invest $60,000 in two simple interest accounts. One account earns 9.4% annual simple interest and the other account earns 10.9% annual simple interest.       Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 87288: An investment club wants to invest $60,000 in two simple interest accounts. One account earns 9.4% annual simple interest and the other account earns 10.9% annual simple interest. How much should be invested in each account so that both accounts earn the same annual interest?

Answer by checkley75(3666) About Me  (Show Source):
You can put this solution on YOUR website!
.094X=.109(60000-X)
.094X=6540-.109X
.094X+.109X=6540
.203X=6540
X=6540/.203
X=32216.75 INVESTED @ 9.4%
60000-32216.75=27783.25 INVESTED @ 10.9%
PROOF
.094*32216.75=.109*27783.25
3028.374=3028.374