SOLUTION: Kabz is 12 years older than Jane. In 10 years twice Kabz's age decrease by Jane's will be 35. Find their ages now.: Kabz is 5 years older than Jane. In 10 years twice Kabz's age
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Question 87286: Kabz is 12 years older than Jane. In 10 years twice Kabz's age decrease by Jane's will be 35. Find their ages now.: Kabz is 5 years older than Jane. In 10 years twice Kabz's age decrease by Jane's will be 35. Find their ages now.
You can put this solution on YOUR website! Write an expression for each phrase
:
"Kabz is 12 years older than Jane."
K = J + 12
:
"In 10 years":
K+10
and
J+10
:
"In 10 yrs twice Kabz's age decrease by Jane's will be 35.
2(K+10) - (J+10) = 35
2K + 20 - J - 10 = 35
2K +10 - J = 35
2K + 10 - 35 = +J
Therefore:
J = 2K - 25
:
Find their ages now.:
Substitute (J+12) for K
J = 2(J+12) - 25
J = 2J + 24 - 25
J - 2J = -1
-J = -1
J = 1 yr old now
:
That makes K = 1+12 = 13 yrs old now
:
Check solution using "In 10 yrs twice Kabz's age decrease by Jane's will be 35.
2(23) - 11 = 35
:
:
Kabz is 5 years older than Jane. In 10 years twice Kabz's age decrease by Jane's will be 35. Find their ages now.
:
K = J + 5
Take the equation we created above:
J = 2K - 25
:
Now substitute (J+5) for K in the above equation:
J = 2(J+5) - 25
J = 2J + 10 - 25
J = 2J - 15
J - 2J = -15
-J = -15
J = 15 yrs old now
Therefore:
K = 15 + 5 = 20 yrs old now
:
Check solution using: "In 10 yrs twice Kabz's age decrease by Jane's will be 35"
2(30) - 25 = 35
:
:
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