SOLUTION: Divided 56 into two parts such that three times the first part exceed one third of second by 48. The parts are
a. 25, 31
b.20,36
c.24, 32
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-> SOLUTION: Divided 56 into two parts such that three times the first part exceed one third of second by 48. The parts are
a. 25, 31
b.20,36
c.24, 32
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Question 872738: Divided 56 into two parts such that three times the first part exceed one third of second by 48. The parts are
a. 25, 31
b.20,36
c.24, 32 Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Divided 56 into two parts such that three times the first part exceed one third of second by 48.
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Part one:: x
Part two:: 56-x
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Equation:
3(56-x)-(1/3)x = 48
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168 - 3x - (1/3)x = 48
-10/3 x = - 120
(1/3)x = 12
x = 36
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56-x = 20
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Cheers,
Stan H.
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The parts are
a. 25, 31
b.20,36
c.24, 32
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