SOLUTION: what does cot^2xsin^2x equal and prove how you got. I try doing this already and got cotx=cosx/sinx cot^2xsinx=(cos^2x/sin^2x)sin^2=cos^2x the problem is that is incorrect sin

Algebra ->  Trigonometry-basics -> SOLUTION: what does cot^2xsin^2x equal and prove how you got. I try doing this already and got cotx=cosx/sinx cot^2xsinx=(cos^2x/sin^2x)sin^2=cos^2x the problem is that is incorrect sin      Log On


   

Question 872664: what does cot^2xsin^2x equal and prove how you got.
I try doing this already and got
cotx=cosx/sinx
cot^2xsinx=(cos^2x/sin^2x)sin^2=cos^2x
the problem is that is incorrect since the question has the following options as the answer
sin^2xcos^2x
1+cos^2tanx
1-tan^2xcos^2x
csc^2x+tan^2x
1+cosxtanx
so where did I go wrong and can you explain step by step how to get he correct answer. That would be great
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
You didn't do anything wrong.
That is the correct answer.
The solutions are not in simplest terms.
One of the solutions does simplify to cos%5E2%28x%29.
I think you should be able to find it fairly easily.
Repost if you get stuck.