SOLUTION: If an object is thrown upward with an initial velocity of 15ft per second, its hight is given by h=-15t^2+90t after t seconds. What it its maximum height?
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Question 872589: If an object is thrown upward with an initial velocity of 15ft per second, its hight is given by h=-15t^2+90t after t seconds. What it its maximum height? Answer by mananth(16949) (Show Source):
You can put this solution on YOUR website! h=-15t^2+90t
the vertex of a parabola is at
x= -b/2a
b=90
a=-15
x= -90/-30
x= 3
plug x = 3 to get the y co ordinate or h
h= -15*(3)^2+90*(3)
h=135 feet the maximum height
