SOLUTION: A simple random sample of 25 cigarettes has a mean tar content of 19.2 and a standard deviation of 4.27. Use a 5% signifiance level to test the claim that the mean tar c

Algebra ->  Probability-and-statistics -> SOLUTION: A simple random sample of 25 cigarettes has a mean tar content of 19.2 and a standard deviation of 4.27. Use a 5% signifiance level to test the claim that the mean tar c      Log On


   

Question 872533: A simple random sample of 25 cigarettes has a mean tar content of 19.2 and a standard deviation of
4.27. Use a 5% signifiance level to test the claim that the mean tar content is less than 21.1

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi



sample 25, mean = 19.2, sd = 4.27

Ho: x  ≥  21.1

Ha: x < 21.1 claim

t = (19.2 - 21.1)/(4.27/sqrt(25) = -1.9/.854 = -2.225

p-value(t < -2.225) (df = 24) = .0179

Reject Ho, The claim that x < 21.1 is valid  (.0179 < .05)