SOLUTION: the lengths of sides of a right angled triangle are respectively 6-x,13-x and 14-x.calculate the lengths of the sides.
let the sides of the triangle be =a,b,&c a=14-x , b=13-
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-> SOLUTION: the lengths of sides of a right angled triangle are respectively 6-x,13-x and 14-x.calculate the lengths of the sides.
let the sides of the triangle be =a,b,&c a=14-x , b=13-
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Question 87246: the lengths of sides of a right angled triangle are respectively 6-x,13-x and 14-x.calculate the lengths of the sides.
let the sides of the triangle be =a,b,&c a=14-x , b=13-x &c=6-x
a^2=b^2+c^2 (14-x)^2=(13-x)^2+(6-x)^2
196-28x+x^2= 169-26x+x^2+36-12x+x^2
=x^2+x^2+169+36-26x-12x-x^2+28x-196
= x^2+205-196-38x+28x
= x^2-10x+9
x^2-10x+9=0 (x-9)(x-1)=0 x-9=0 x=9 or x-1=0 or x=1
therefore if x=9 then a=14-9=5,b=13-9=4 &c=6-9=-3
if x=1 then a=14-1=13, b=13-1=12 &c=6-1=5 Answer by malakumar_kos@yahoo.com(315) (Show Source):
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