You can put this solution on YOUR website! Solve algebraically for x : 16^x+4 = 64^x+1
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If you mean:
16^(x+4) = 64^(x+1)
4^(2x+8) = 4^(3x+3)
2x+8 = 3x+3
x = 5
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The long way:
(x+4)*log(16) = (x+1)*log(64)
x*log(16) + 4log(16) = x*log(64) + log(64)
x*(log(16) - log(64)) = log(64) - log(65536)
x = log(1/1024)/log(1/4)
x = 5
16 and 64 are both powers of 4
So we write 16 as 4² and 64 as 4³
Remove the parentheses by multiplying the exponents:
Equal exponentials with the same positive base ≠ 1
have equal exponents:
Edwin
