Hi
Below:  z = 0, z = ± 1, z= ±2 , z= ±3 are plotted.  
Note: z = 0 (x value the mean) 50% of the area under the curve is to the left 
and %50 to the right

Population: mean = 3962, SD = 950
a) P(x ≥ 1000) = -2962/950 = -3.118
   P(z > -3.118) = normalcdf( -3.118, 10) = .9991  0r 99.91%
b) invNorm(.90) = 1.28,   1.28*950 + $3962 = $5178 (10% owe more than this)
c) As a Rule: 2SD on either side of mean: is 95% of the Population
   3962 - 2*950 < x < 3962 + 2*950
For the normal distribution: 
one  standard deviation from the mean accounts for about 68% of the set 
two standard deviations from the mean account for about 95%
and three standard deviations from the mean account for about 99.7%.