SOLUTION: This is the problem:
3z/z^2-9 - 2/3-z
and this is what I've come up with...Is it correct?
5z+6/(z-3)(z+3)
Thanks!
Algebra ->
College
-> Linear Algebra
-> SOLUTION: This is the problem:
3z/z^2-9 - 2/3-z
and this is what I've come up with...Is it correct?
5z+6/(z-3)(z+3)
Thanks!
Log On
Question 87210: This is the problem:
3z/z^2-9 - 2/3-z
and this is what I've come up with...Is it correct?
5z+6/(z-3)(z+3)
Thanks! Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! 3z/z^2-9 - 2/3-z
---------
3z/[(z-3)(z+3)] + [2(z+3)]/[(z-3)(z+3)]
=[5z+6] / [z^2-9]
=================
Cheers,
Stan H.
(