SOLUTION: Hi! I'd appreciate any help with this one. 5a^2 - 20/3a^2-12a divided by (a^3+2a^2/2a^2-8a * 9a^3 + 6a^2/ 2a^2-4a I know the answer is 4a^2/9(a-1) but, I don't know how to get

Algebra ->  Expressions -> SOLUTION: Hi! I'd appreciate any help with this one. 5a^2 - 20/3a^2-12a divided by (a^3+2a^2/2a^2-8a * 9a^3 + 6a^2/ 2a^2-4a I know the answer is 4a^2/9(a-1) but, I don't know how to get       Log On


   



Question 87209: Hi! I'd appreciate any help with this one.
5a^2 - 20/3a^2-12a divided by (a^3+2a^2/2a^2-8a * 9a^3 + 6a^2/ 2a^2-4a
I know the answer is 4a^2/9(a-1) but, I don't know how to get there. Or how to get rid of the 5 and how to get the (a-1).
Thanks so much for your help!

Answer by longjonsilver(2297) About Me  (Show Source):
You can put this solution on YOUR website!
Not sure what you meant... not enough brackets used...



not sure where the 9a^2 should be.


cheers
Jon