SOLUTION: rewrite middle term as the sum of two terms and factor completely 1.12w^2+19w+4 2.4z^3-18z^2-10z

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Question 87196: rewrite middle term as the sum of two terms and factor completely
1.12w^2+19w+4


2.4z^3-18z^2-10z


Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
In order to factor 12%2Aw%5E2%2B19%2Aw%2B4, first multiply 12 and 4 to get 48 and we need to ask ourselves: What two numbers multiply to 48 and add to 19? Lets find out by listing all of the possible factors of 48

Factors:
1,2,3,4,6,8,12,16,24,48,
-1,-2,-3,-4,-6,-8,-12,-16,-24,-48, List the negative factors as well. This will allow us to find all possible combinations
These factors pair up to multiply to 48.
1*48=48
2*24=48
3*16=48
4*12=48
6*8=48
(-1)*(-48)=48
(-2)*(-24)=48
(-3)*(-16)=48
(-4)*(-12)=48
(-6)*(-8)=48
note: remember two negative numbers multiplied together make a positive number
Now which of these pairs add to 19? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to 19
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First Number|Second Number|Sum
1|48|1+48=49
2|24|2+24=26
3|16|3+16=19
4|12|4+12=16
6|8|6+8=14
-1|-48|-1+(-48)=-49
-2|-24|-2+(-24)=-26
-3|-16|-3+(-16)=-19
-4|-12|-4+(-12)=-16
-6|-8|-6+(-8)=-14
We can see from the table that 3 and 16 add to 19. So the two numbers that multiply to 48 and add to 19 are: 3 and 16
So the original quadratic

12%2Aw%5E2%2B19%2Aw%2B4

breaks down to this (just replace 19%2Aw with the two numbers that multiply to 48 and add to 19, which are: 3 and 16)

12%2Aw%5E2%2B3w%2B16w%2B4
Group the first two terms together and the last two terms together like this:
%2812%2Aw%5E2%2B3w%29%2B%2816w%2B4%29
Factor a 3 out of the first group and factor a 4 out of the second group.

3w%284w%2B1%29%2B4%284w%2B1%29

Now since we have a common term 4w%2B1 we can combine the two terms. Notice if we let y=4w%2B1 we would get 3wy%2B4y=%283w%2B4%29y. Since we have that common term y, we are able to combine 3w and 4

%283w%2B4%29%284w%2B1%29 Combine like terms.
Answer:
So the quadratic 12%2Aw%5E2%2B19%2Aw%2B4 factors to

%283w%2B4%29%284w%2B1%29


Notice how %283w%2B4%29%284w%2B1%29 foils back to our original problem 12%2Aw%5E2%2B19%2Aw%2B4. This verifies our answer.




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4z%5E3-18z%5E2-10z+

z%284z%5E2-18z-10%29+ Factor out a "z"

Now lets factor the quadratic inside the parenthesis

In order to factor 4%2Az%5E2-18%2Az-10, first multiply 4 and -10 to get -40 and we need to ask ourselves: What two numbers multiply to -40 and add to -18? Lets find out by listing all of the possible factors of -40

Factors:
1,2,4,5,8,10,20,40,
-1,-2,-4,-5,-8,-10,-20,-40, List the negative factors as well. This will allow us to find all possible combinations
These factors pair up to multiply to -40.
(-1)*(40)=-40
(-2)*(20)=-40
(-4)*(10)=-40
(-5)*(8)=-40
Now which of these pairs add to -18? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to -18
||||||||
First Number|Second Number|Sum
1|-40|1+(-40)=-39
2|-20|2+(-20)=-18
4|-10|4+(-10)=-6
5|-8|5+(-8)=-3
-1|40|(-1)+40=39
-2|20|(-2)+20=18
-4|10|(-4)+10=6
-5|8|(-5)+8=3
We can see from the table that 2 and -20 add to -18. So the two numbers that multiply to -40 and add to -18 are: 2 and -20
So the original quadratic

4%2Az%5E2-18%2Az-10

breaks down to this (just replace -18%2Az with the two numbers that multiply to -40 and add to -18, which are: 2 and -20)

4%2Az%5E2%2B2z-20z-10
Group the first two terms together and the last two terms together like this:
%284%2Az%5E2%2B2z%29%2B%28-20z-10%29
Factor a 2 out of the first group and factor a -10 out of the second group.

2z%282z%2B1%29-10%282z%2B1%29

Now since we have a common term 2z%2B1 we can combine the two terms. Notice if we let y=2z%2B1 we would get 2zy-10y=%282z-10%29y. Since we have that common term y, we are able to combine 2z and -10

%282z-10%29%282z%2B1%29 Combine like terms.
Answer:
So the quadratic 4%2Az%5E2-18%2Az-10 factors to

%282z-10%29%282z%2B1%29


Notice how %282z-10%29%282z%2B1%29 foils back to our original problem 4%2Az%5E2-18%2Az-10. This verifies our answer.



So now reintroduce the z term we factored out back in:

z%282z-10%29%282z%2B1%29

So the expression

4z%5E3-18z%5E2-10z+

factors to this

z%282z-10%29%282z%2B1%29

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