SOLUTION: What is the equation of the line passing throughhe point (2,0)? y=-2x-1 y=(1/2)x-1 y=x-4 y=3x+3

Algebra ->  Graphs -> SOLUTION: What is the equation of the line passing throughhe point (2,0)? y=-2x-1 y=(1/2)x-1 y=x-4 y=3x+3      Log On


   

Question 87194: What is the equation of the line passing throughhe point (2,0)?
y=-2x-1
y=(1/2)x-1
y=x-4
y=3x+3
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
y=2x-1 Start with the possible equation

0=2%282%29-1 Plug in x=2 and y=0

0=3 Simplify. Since this is not true, the point does not lie on this line
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y=%281%2F2%29x-1 Start with the possible equation

0=%281%2F2%29%282%29-1 Plug in x=2 and y=0

0=0 Simplify. Since this is true, the point lies on this line


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y=x-4 Start with the possible equation

0=%282%29-4 Plug in x=2 and y=0

0=-2 Simplify. Since this is not true, the point does not lie on this line


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y=3x-1 Start with the possible equation

0=3%282%29-1 Plug in x=2 and y=0

0=5 Simplify. Since this is not true, the point does not lie on this line


So to recap, the point (2,0) only lies on the line y=%281%2F2%29x-1