SOLUTION: find the natural number which when added to its square gives 9 times the next natural number
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Question 871932
:
find the natural number which when added to its square gives 9 times the next natural number
Answer by
mananth(16946)
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let the number be x
next number will be (x+1)
x+x^2=9(x+1)
x+x^2=9x+9
x^2-8x-9=0
x^2-9x+x-9=0
x(x-9)+1(x-9)=0
(x-9)(x+1)=0
so
x=9 OR -1
ignore negative since number is natural