SOLUTION: cos(angle beta)= -15/17 and 180degrees<(angle beta)<270degrees find tan 2(angle beta) thats a question in my precalculus class *Note, i dont have all math symbols so i substit

Algebra ->  Trigonometry-basics -> SOLUTION: cos(angle beta)= -15/17 and 180degrees<(angle beta)<270degrees find tan 2(angle beta) thats a question in my precalculus class *Note, i dont have all math symbols so i substit      Log On


   

Question 871548: cos(angle beta)= -15/17 and 180degrees<(angle beta)<270degrees
find tan 2(angle beta)
thats a question in my precalculus class
*Note, i dont have all math symbols so i substituded them with their real names
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi

cos θ = -15/17

3rd Quadrant Stated:  sinθ = -8/17   sqrt%2817%5E2-15%5E2%29+=+8

tan θ = sinθ/cosθ = 8/15

(cosx, sinx) Unit Circle Summary Reference Below

Wish You the Best in your Studies.