You can put this solution on YOUR website! Three consecutive odd integers whose sum is 357 ?
Let the three consecutive odd integers be:
n, n + 2 and n + 4
Therefore:
n + n + 2 + n + 4 = 357
3n + 6 = 357
Subtract 6 from each side of the equation.
3n = 351
Divide each side by 3.
3n/3 = 351/3
n = 117
n + 2 = 119
n + 4 = 121