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If a ball is shot upward from ground level with an initial velocity of 136 feet per second, after t seconds, its height h in feet is given by the formula h=-16t
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If a ball is shot upward from ground level with an initial velocity of 136 feet per second, after t seconds, its height h in feet is given by the formula h=-16t
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Question 871465: Anyone can help?
If a ball is shot upward from ground level with an initial velocity of 136 feet per second, after t seconds, its height h in feet is given by the formula h=-16t^2 + 136t. After how many seconds will it hit the ground? Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! If a ball is shot upward from ground level with an initial velocity of 136 feet per second, after t seconds, its height h in feet is given by the formula h=-16t^2 + 136t. After how many seconds will it hit the ground?
If a ball is shot upward from ground level with an initial velocity of 136 feet per second, after t seconds, its height h in feet is given by the formula
h=-16t^2 + 136t.
At two times the ball will be on ground
once when starting and once when it lands
h=0
h=-16t^2 + 136t.
16t^2=136t
t=136/16
t=17/2
t=8.5 seconds
