SOLUTION: In a 3-digit number, the sum of the tens and units digits is 5 less than the hundreds digit. If the digits are reversed, the new number is 495 less than the old number. The sum of
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Question 871350: In a 3-digit number, the sum of the tens and units digits is 5 less than the hundreds digit. If the digits are reversed, the new number is 495 less than the old number. The sum of the digits of the number is 7. Find the old number. Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! In a 3-digit number, the sum of the tens and units digits is 5 less than the hundreds digit. If the digits are reversed, the new number is 495 less than the old number. The sum of the digits of the number is 7. Find the old number.
xyz
y+z=x-5
100z+10y+x=100x+10y+z-495
-99x+99z=-495
/99
-x+y=5
y-x=-5
x+y+z=9
substitute (y+z)=(x-5)
x+x-5=9
2x=14
x=7
Now y+z=7-5
y+z=2
Now y-x=-5
y-7=-5
y=2
x+y=9
Therefore x=0
The number is 720
