SOLUTION: Find the vertex, focus, directrix, and opening of 4x^2 - 24x - 6y + 12 =0.

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Find the vertex, focus, directrix, and opening of 4x^2 - 24x - 6y + 12 =0.       Log On


   

Question 871299: Find the vertex, focus, directrix, and opening of 4x^2 - 24x - 6y + 12 =0.
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi

4x^2 - 24x - 6y + 12 =0. 

4x^2 - 24x = 6y - 12 

4(x-3)^2 - 36 = 6y - 12 

4(x-3)^2 -24 = 6y 

y = (2/3)(x-3)^2 - 4  V(3,-4) Parabola opening Upward.  Axis of symmetry x = 3

1%2F%284p%29+=+2%2F3, p = %28%283%2F2%29%2F4%29 = 3/8  F(3, -3 5/8)  y = -4 3/8