Question 871129: A couple plans to have 5 children. Find the probability they will have more than 3 boys. ( Assume girl and boy babies are equally likely.) Answer by ewatrrr(24785) (Show Source):
You can put this solution on YOUR website! p(boy) = .5, n = 5
P(x ≥ 3) = 1 - binomcdf(5, .5, 2) = .5
0r
Using
P(x ≥ 3) = P(x=3)+P(x=4)+P(x=5) = .3125 + .15625 + .03125