SOLUTION: I really need help on these two questions /: Thanks in advance!!! Picture of the problems can be found here: https://answers.yahoo.com/question/index?qid=20140505210315AAgZFc6

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: I really need help on these two questions /: Thanks in advance!!! Picture of the problems can be found here: https://answers.yahoo.com/question/index?qid=20140505210315AAgZFc6      Log On


   

Question 871029: I really need help on these two questions /:
Thanks in advance!!!
Picture of the problems can be found here: https://answers.yahoo.com/question/index?qid=20140505210315AAgZFc6
Answer by josgarithmetic(39630) About Me  (Show Source):
You can put this solution on YOUR website!
Those require knowing synthetic division. If an alternative is permitted, this would be polynomial division. Explaining synthetic division here is very difficult, but a mostly easy process.

Your number 17 looks like %28x%5E3%2B5x%5E2%2Bx-15%29%2F%28x%2B3%29. Synthetic division is a way to check a possible "root" of -3. Write the dividend as the row of coefficients; and show the root to test to the left of the dividend.


Pull down the 1, multiply by the divisor, put this product under the 5:
-
____________________________________________
_________|
____-3___|____1_____5_____1______-15
_________|__________-3
_____________________________________________
______________1


Add the column of the 5 and -3; put this result on the bottom row.
_____________________________________________
_________|
____-3___|____1_____5_____1______-15
_________|_________-3
_____________________________________________
______________1_____2


Multiply the 2 by the divisor and put the result under the next part of the dividend. Then add the column.
_____________________________________________
_________|
____-3___|____1_____5_____1______-15
_________|_________-3____-6
_____________________________________________
______________1_____2_____-5


Multiply this result by the divisor and put the product under the last part of the dividend, the -15:
_____________________________________________
_________|
____-3___|____1_____5_____1______-15
_________|_________-3____-6______15
_____________________________________________
______________1_____2_____-5


Now add the column values:

_____________________________________________
_________|
____-3___|____1_____5_____1______-15
_________|_________-3____-6______15
_____________________________________________
______________1_____2_____-5______0


DONE. The remainder is zero.
The bottom row of numbers corresponds the coefficients of the quotient of the division as highlight%28x%5E2%2B2x-5%29.