SOLUTION: factor completely: 20x^2+49x+30 GCF is 1. i dont know where to go from there.

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: factor completely: 20x^2+49x+30 GCF is 1. i dont know where to go from there.      Log On


   

Question 870945: factor completely: 20x^2+49x+30
GCF is 1. i dont know where to go from there.
Answer by ben720(159) About Me  (Show Source):
You can put this solution on YOUR website!
20x%5E2%2B49x%2B30
First find the product of 20*30: 600. Next find two factors of 600 that add up to 49. Those will be 24 and 25. Split the 49x into 24x+25x:
20x%5E2%2B24x%2B25x%2B30
Use parentheses
%2820x%5E2%2B24x%29%2B%2825x%2B30%29
Factor the terms
4x%285x%2B6%29%2B5%285x%2B6%29
Use the Converse of the Distributive Property
%284x%2B5%29%285x%2B6%29