SOLUTION: Solve the equation by graphing. If exact roots cannot be found, state the consecutive integers between which the roots are located. x^2+8x+14=0

Algebra ->  Rational-functions -> SOLUTION: Solve the equation by graphing. If exact roots cannot be found, state the consecutive integers between which the roots are located. x^2+8x+14=0      Log On


   

Question 870790: Solve the equation by graphing. If exact roots cannot be found, state the consecutive integers between which the roots are located.
x^2+8x+14=0
Found 2 solutions by ewatrrr, josgarithmetic:
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
x^2+8x+14=0
x+=+%28-8+%2B-+sqrt%28+8%29%29%2F%282%29+
x = -4 ± √2
x = -2.586 between -2 and -3
x = -5.414 between -5 and -6

Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
Just by graphing? Use general solution of the quadratic equation to find the roots and then draw the graph. If computing the discriminant gives a negative number, then no real roots can be shown.

8%5E2-4%2A1%2A14=64-4%2A14=64-56=8

The x-intercepts will be two irrational values.
zeros or roots are %28-8-sqrt%288%29%29%2F2 and %28-8%2Bsqrt%288%29%29%2F2;
or -4-sqrt%282%29 and -4%2Bsqrt%282%29%29. Those are exact irrational real roots.

graph%28200%2C200%2C-6%2C1%2C-4%2C3%2Cx%5E2%2B8x%2B14%29