SOLUTION: Please explain how to solve the equation for exact solutions over the interval [0, 2pi). 2cos^2x - sqrt(3)cosx = 0

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Question 870598: Please explain how to solve the equation for exact solutions over the interval [0, 2pi).
2cos^2x - sqrt(3)cosx = 0
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Factor.
2cos%5E2%28x%29+-+sqrt%283%29cos%28x%29+=+0
cos%28x%29%282cos%28x%29+-+sqrt%283%29%29+=+0
Two solutions:
cos%28x%29=0
x=pi%2F2 and x=%283%2F2%29pi
and
2cos%28x%29-sqrt%283%29=0
cos%28x%29=sqrt%283%29%2F2
x=pi%2F6 and x=%2811%2F6%29pi