SOLUTION: Here is the question: Sandy left the city for vacation. Sam left 6 hours later going 75 mph faster to catch up. After 5 hours Sam caught up. What was Sandy's average speed? I ha

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Question 870379: Here is the question: Sandy left the city for vacation. Sam left 6 hours later going 75 mph faster to catch up. After 5 hours Sam caught up. What was Sandy's average speed?
I have made a chart to try to solve, but as we have not studied this time of d=rt I am unable to solve it. Thank you for any help.

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
It took Sandy 11 hours to ttravel the same distance that Sam took 5 hours.
R%5Bs%5D%2A11=5%2A75
R%5Bs%5D=%285%2F11%29%2A75
R%5Bs%5D=34.9mph