SOLUTION: Two cars leave City A at the same time to travel to city B. One car travels at 72 km/h and other at 78 km/h. If the slower car arrives 20 min. after the faster car, how far apart a
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Question 87012: Two cars leave City A at the same time to travel to city B. One car travels at 72 km/h and other at 78 km/h. If the slower car arrives 20 min. after the faster car, how far apart are City A and City B? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Two cars leave City A at the same time to travel to city B. One car travels at 72 km/h and other at 78 km/h. If the slower car arrives 20 min. after the faster car, how far apart are City A and City B?
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1st Car DATA:
Rate = 72 km/h ; Time = x hrs ; distance = 72x km
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2nd Car DATA:
Rate = 78 km/h ; Time = (x-(1/3)) hrs ; distance = 78(x-(1/3)) km
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EQUATION:
distance = distance
72x = 78(x - (1/3))
72x = 78x - 26
6x= 26
x = 13/3 hrs
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So, how far is it from A to B?
72 km/h *(x hr) = 72(13/3) = 24*13 = 312 km
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Cheers,
Stan H.
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